正确答案:CDEC,D,E 解析:Explanation:Since the subnet mask is 255.255.255.224, the number of network hosts that is available is 30. Every network boundary will be a multiple of 32. This means that every subnet will be a multiple (0, 32, 64, 96, 128, 160, 192, 224) and the broadcast address for each of these subnets will be one less this number (31, 63, 95, 127, 159, 191, 223). Therefore, any IP address that does not end in one of these numbers will be a valid host IP address.C. Valid Host in subnetwork 2 (92.11.178.64 to 92.11.178.95)D. Valid Host in subnetwork 1 (134.178.18.32 to 134.178.18.63)E. Valid Host in subnetwork 2 (192.168.16.64 to 192.168.16.95)Incorrect Answers:A. This will be the broadcast address for the 16.23.118.32/27 network.B. This will be the broadcast address for the 87.45.16.128/27 networkF. This will be the network address for the 217.168.166.192/27 network.